Please help me ASAP!!!! Find the value of x

Use Pythagorean theory
C^2 = a^+ b^2
In this case you have c and a
B^2= c^2-a^2
B^2 = 12^2-5^2
B^2= 144-25
B^2 = 119
Square root both sides
X= 10.90871
This is a right triangle and to find the length of the missing side you must do pythagorean theorem:
[tex]a^{2} +b^{2} = c^{2}[/tex]
a & b are the legs of a right triangle
c is the hypotenuse. This is the side opposite the right angle
In this case each value is:
a = 5
b = x---------------> This is what you are looking for
c = 12
^^^Plug these number into the pythagorean theorem
[tex]5^{2} +x^{2} = 12^{2}[/tex]
25 + [tex]x^{2}[/tex] = 144
Isolate x by subtracting 25 to both sides
[tex](25-25) + x^{2} = 144 - 25[/tex]
[tex]x^{2} = 119[/tex]
The opposite of squaring a number is taking the square root of a number, so to isolate x take the square root of both sides.
[tex]\sqrt{x^{2} } } =\sqrt{119}[/tex]
x = 10.9087121146
Then if the question requests it, you can round 10.9087121146
Hope this helped!