Answer:
191.4 g.
Explanation:
- The balanced equation for the mentioned reaction is:
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g),
It is clear that 1.0 mole of Fe₂O₃ react with 3.0 mole of CO to produce 2.0 moles of Fe and 3.0 moles of CO₂.
Using cross multiplication:
2.0 mol of Fe produced with → 3.0 mol of CO₂, from stichiometry.
2.9 mol of Fe produced with → ??? mol of CO₂.
∴ The no. of moles of CO₂ produced = (3.0 mol)(2.9 mol)/(2.0 mol) = 4.35 mol.
∴ The mass of CO₂ produced = no. of moles x molar mass = (4.35 mol)(44.0 g/mol) = 191.4 g.
