Answer:
The volume of the pyramid is [tex]130\frac{2}{3}\ units^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the pyramid is equal to
[tex]V=\frac{1}{3}BH[/tex]
where
B is the area of the base
H is the height of the pyramid
Find the area of the base B
In this problem we have a square base
[tex]B=7^{2} =49\ units^{2}[/tex]
we have
[tex]H=8\ units[/tex]
substitute
[tex]V=\frac{1}{3}(49)(8)=\frac{392}{3}\ units^{3}[/tex]
Convert to mixed number
[tex]\frac{392}{3}=\frac{390}{3}+\frac{2}{3}=130\frac{2}{3}\ units^{3}[/tex]
