Respuesta :

aguilerapablo03

±1/2. The equation [tex]4x^{2} =1[/tex] has two possible solutions +1/2 and -1/2.

The problem is a quadratic equations and it can be solved using the equation [tex]x=-b±\frac{\sqrt{b^{2} -4ac} }{2a}[/tex].

Ordering the quadratic equation given in the problem, we obtain [tex]4x^{2} -1=0[/tex] where a = 4, b = 0, and c = -1

Substituting the values

[tex]x=±\frac{\sqrt{-4(4)(-1)} }{2(4)}=±\frac{\sqrt{16}}{8} =±\frac{4}{8} \\x=±\frac{1}{2}[/tex]

mixter17

Hello!

The answer is:

The correct option is the second option,

[tex]4x^{2}=+-\frac{1}{2}[/tex]

Why?

We are given the expression:

[tex]4x^{2}[/tex]

Now, solving we have:

Applying square root to both sides of the equation in order to isolate x:

[tex]4x^{2}=1\\\\\sqrt{4x^{2} } =+-\sqrt{1}\\\\2x=+-1\\\\x=+-\frac{1}{2}[/tex]

Hence, the correct option is the second option,

[tex]4x^{2}=+-\frac{1}{2}[/tex]

Have a nice day!

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