Answer:
Both a and b are independent (see explanation)
Step-by-step explanation:
Events A and B are independent when
[tex]P(A\cap B)=P(A)\cdot P(B)[/tex]
a) A - "winning"
B - "playing at home"
From the table,
[tex]P(A)=0.25\\ \\P(B)=0.8\\ \\P(A\cap B)=0.2[/tex]
Since
[tex]0.25\cdot 0.8=0.2[/tex]
events are independent.
b) A - "losing"
B - "playing away"
From the table,
[tex]P(A)=0.75\\ \\P(B)=0.2\\ \\P(A\cap B)=0.15[/tex]
Since
[tex]0.75\cdot 0.2=0.15[/tex]
events are independent.