Respuesta :

r3t40

I'll do both.

[tex]

5x-97>-34\Rightarrow x>\frac{-34+97}{5}=\frac{63}{5}=\boxed{12.6} \\

\boxed{x\in(12.6, \infty)} \\ \\

2x+31<29\Longrightarrow x<29-31=\boxed{-2} \\

\boxed{x\in(-\infty, -2)}

[/tex]