Respuesta :
Answer:
We use the general gas law or the combined gas law to solve this kind of problem
Explanation:
The general gas law is a combination of both Boyle's law and Charle's law. It is expressed as:
[tex]\frac{ P₁V₁}{T₁}[/tex] = [tex]\frac{ P₂V₂}{T₂}[/tex]
The unkown is V₂ which can be derived by substituting in the equation above.
The general gas law assumes that, n, the number of mole is 1
Answer: To determine the final Volumen of the gas we use the Combined gas law
Explanation:
The combined gas law combines three gas laws: Boyle's Law, Charles' Law, and Gay-Lussac's Law, this law links pressure, volume, and temperature of a giving gas, from initial conditions ( expressed with the number 1) to final conditions (expressed with the number 2)
P1V1 / T1 = P2V2 / T2
- In our exercise, we state the initial conditions of the gas, ( keep in mind that this law works only with absolute temperatures, then we need to convert degrees Celsius to the Kelvin scale)
P1 = 745 mm Hg
V1 = 1,56 L
T1 = 27°C + 273,17K = 300.15 K
- Now we state the final conditions and the parameter we need to calculate
P2 = 700 mm Hg
V2 = x (the unknown you're solving for)
T2 = 100°C + 273,15K = 373.15 K
- Finally, we take the formula and we isolate the V2 that we are interested in and fill in the rest with the information giving.
V2 = (P1 V1 T2) / (P2 T1)
V2= (745 mm Hg . 1,56 L . 373.15 K) / ( 700 mm Hg . 300.15 K )
V2 = 2,06 L