Answer: The answer is: " 2pq " .
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Note: (p+q) (p+q) = ?
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Note the following "distributive property" of multiplication:
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(a + b) (c + d) = ac + ad + bc + bd ;
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As such:
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(p + q) (p + q) = pp + pq + qp + qq ;
→ = pp + pq + pq + qq ;
Combine the "like terms:
pq + pq = 2pq ; Note there these are the "heterozygous" individuals in the population; since these represent "2 different alleles" ;
= p² + 2pq + q² ;
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Since: "pp" ; or: "p² " is: "homozygous" (the same 2 alleles)" ;
and since: "qq" ; or: "q² " is: "homozygous (the same 2 alleles)" .
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