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At what temperature (in C) will a sample of gas occupy 91.3 L if it occupies 45.0 L at 70.0°C? Assume constant pressure.)

Respuesta :

romannp

Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

Eduard22sly

The temperature at which the sample of gas occupy 91.3 L is 422.9 °C

From the question given above, the following data were obtained:

Initial volume (V₁) = 45 L

Initial temperature (T₁) = 70 °C = 70 + 273 = 343 K

Final volume (V₂) = 91.3 L

Pressure = constant

Final temperature (T₂) =?

The final temperature of gas can be obtained by using the Charles' law equation as illustrated below:

[tex] \frac{V_1}{T_1} = \frac{V_2}{T_2} \\ \\ \frac{45}{343} = \frac{91.3}{T_2} \\ \\ cross \: multiply \\ \\ T_2 \times 45 = 343 \times 91.3 \\ \\ divide \: both \: side \: by \: 45 \\ \\ T_2 = \frac{343 \times 91.3}{45} \\ \\ T_2 = 695.9 \: K \\ \\ T_2 = 695.9 - 273 \\ \\T_2 = 422.9\degree \: C[/tex]

Therefore, the temperature at which the sample of gas occupy 91.3 L is 422.9 °C

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