Answer:
0.004167 J/g°C is the specific heat of a substance.
Explanation:
[tex]Q=m\times c\times \Delta T[/tex]
[tex]Q=m\times c\times (T_{2}-T_1)[/tex]
Where:
Q = heat absorbed(positive) or released (negative)
m = Mass of substance
c = specific heat of a substance
[tex]T_1[/tex] = Initial temperature
[tex]T_2[/tex] = Final temperature
We have:
m = [tex]1.0\times 10^4 g[/tex]
c = ? , [tex]T_1=10^oC,T_2=70^oC[/tex]
Q = [tex]2.5\times 10^3 J[/tex]
[tex]2.5\times 10^3 J=1.0\times 10^4 g\times c\times (70^oC-10^oC)[/tex]
[tex]c=\frac{2.5\times 10^3 J}{1.0\times 10^4 g\times (70^oC-10^oC)}[/tex]
[tex]c=0.004167 J/g^oC[/tex]
0.004167 J/g°C is the specific heat of a substance.
