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If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb's constant is k = 9.0x 10^9 N-m^2/C^2? 9.5 m 9.0 mm 9.5 cm 0.9 m .

Respuesta :

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge [tex]q= 10^{-6}\ C[/tex]

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

[tex]F = \dfrac{kq_{1}q_{2}}{r^2}[/tex]

Where, q = charge

r = distance

F = force

Put the value into the formula

[tex]1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}[/tex]

[tex]r=\sqrt{9\times10^{9}\times(-10^{-6})^2}[/tex]

[tex]r=0.095\ m[/tex]

[tex]r= 9.5\ cm[/tex]

Hence, The distance between the charges is 9.5 cm