Respuesta :
[tex]x^2-5\leq0\\x^2\leq5\\x\leq \sqrt5 \wedge x\geq-\sqrt5\\x\in\left\langle-\sqrt5,\sqrt5\right\rangle[/tex]
For this case we must indicate the solution of the following inequality:
[tex]x ^ 2-5 \leq0[/tex]
Adding 5 to both sides of the inequality:
[tex]x ^ 2\leq5[/tex]
We apply square root on both sides of the inequality to eliminate the exponent:
[tex]x \leq\pm \sqrt {5}[/tex]
So, we have two solutions:
[tex]x\leq \sqrt {5}[/tex]
Since it is an inequality, the sign for the negative portion is changed:
[tex]x\geq- \sqrt {5}[/tex]
Answer:
[tex]x\leq \sqrt {5}\\x\geq-\sqrt {5}[/tex]