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Calculate the molarity of the solution.
6.02 x 1022 molecules of HCI (molecular weight = 36.5 g/mole) in 2.0 liters of water
M

Respuesta :

Answer:

ans. is 0.05

Explanation:

molarity=(mole of solute)/(litre of solution)

Answer:

The molarity of the solution is 0.05 [tex]\frac{moles}{L}[/tex]

Explanation:

Molarity (M) is the number of moles of solute that are dissolved in a given volume.

Molarity is determined by the following expression:

[tex]Molarity (M)=\frac{number of moles of solute}{dissolution volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

Then you should know the amount of moles of HCL. For that you should know that:

The Avogadro Number or Avogadro Constant is called the number of particles that constitute a substance (usually atoms or molecules) and that can be found in the amount of one mole of that substance.  Its value is 6.023 * 10²³ particles per mole. Avogadro's number applies to any substance.

Therefore, applying a rule of three, 6.02*10²² molecules correspond to:

[tex]moles=\frac{6.02*10^{22}*1mole }{6.023*10^{23} }[/tex]

moles=0.1 moles of HCl

Applying the definition of molarity:

[tex]M=\frac{0.1 moles}{2 L}[/tex]

M= 0.05 [tex]\frac{moles}{L}[/tex]

The molarity of the solution is 0.05 [tex]\frac{moles}{L}[/tex]