Answer:
The force exerted by the floor is 80 N.
Explanation:
Given that,
Mass of ball = 0.5 kg
Velocity= 4 m/s
Time t = 0.05 s
When the ball rebounds then the kinetic energy is
[tex]K.E =\dfrac{1}{2}mv^2[/tex]
Where, m = mass of ball
v = velocity of ball
Put the value into the formula
[tex]K.E=\dfrac{1}{2}\times0.5\times(4)^2[/tex]
[tex]K.E = 4\ J[/tex]
The average force exerted by the floor on the ball = change in kinetic energy over collision time
[tex]F = \dfrac{4}{0.05}[/tex]
[tex]F=80\ N[/tex]
Hence, The force exerted by the floor is 80 N.
