Answer:
[tex]x_1=-2.9\\x_2=0.2[/tex]
Step-by-step explanation:
The first step is to move the [tex]5x[/tex] to the left side of the equation and then add the like terms:
[tex]4x^2+16x-2=5x\\\\4x^2+16x-2-5x=0\\\\4x^2+11x-2=0[/tex]
Now we can apply the Quadratic formula. This is:
[tex]x=\frac{-b\±\sqrt{b^2-4ac}}{2a}[/tex]
In this case we can identify that:
[tex]a=4\\b=11\\c=-2[/tex]
Finally, we must substitute these values into the Quadratic formula. Then we get:
[tex]x=\frac{-11\±\sqrt{(11)^2-4(4)(-2)}}{2(4)}[/tex]
[tex]x_1=-2.9\\x_2=0.2[/tex]
