Respuesta :

[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 7.25\%\to \frac{7.25}{100}\dotfill &0.0725\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{weekly, fifty two times} \end{array}\dotfill &52\\ t=years\dotfill &24 \end{cases}[/tex]

[tex]\bf A=20000\left(1+\frac{0.0725}{52}\right)^{52\cdot 24}\implies A\approx 20000(1.001394)^{1248} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 113776.1384~\hfill[/tex]