Answer:
[tex]\sqrt[2]{x^3}[/tex]
Step-by-step explanation
First thing you should do is change the decimal into a fraction,
In this problem you have one whole plus a half. So you can rewrite that into [tex]1\frac{1}{2}[/tex]. Which is the same thing as [tex]\frac{3}{2}[/tex]
Why [tex]\frac{3}{2}[/tex] ?
Because one whole number is the same as [tex]\frac{1}{1},\frac{2}{2},\frac{3}{3},\frac{4}{4},\frac{5}{5}[/tex] since all of those numbers divided by themselves equals to one. You'll take [tex]\frac{2}{2}[/tex] and add it with [tex]\frac{1}{2}[/tex].
Now since we have [tex]x^\frac{3}{2}[/tex], THE DENOMINATOR WILL BECOME THE SQUARE ROOTS NUMBER, AND THE NUMERATOR WILL BE EXPONENT.
So it becomes, [tex]\sqrt[2]{x^3}[/tex]
