an official playing field (including end zone) for the indoor football league has a length 45 yd longer than its width. the perimeter of the rectangular field is 174 yd. find the length ​

Respuesta :

So you know the perimeter form is = 2(l + w) or l + l + w + w

So the length is 45 + w following the formula

2(45 + w) + 2w = 174

90 + 2w + 2w = 174

4w = 84
w= 21

So the length is 45 + w, w= 21

45+ 21 = 66

Hope this helps!


The width of the field is 21 yds, while the length of the rectangular field is 66 yds.

What is the perimeter?

Perimeter is the sum of the length of the sides used to make the given figure.

Let the width of the field be represented by x yds., then the length of the field will be (x+45) yds. The perimeter of the rectangular field is 174 yds. Therefore, we can write,

174 = 2[x+(x+45)]

174 = 2(2x+45)

174 = 4x + 90

84 = 4x

x = 21 yds.

Hence, the width of the field is 21 yds, while the length of the rectangular field is 66 yds.

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