Respuesta :

[tex]\bf \textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{-4}x\stackrel{\stackrel{c}{\downarrow }}{+6} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{-4}{2(1)}~~,~~6-\cfrac{(-4)^2}{4(1)} \right)\implies (2~~,~~6-4)\implies (2~,~2)[/tex]

Answer:

B. (2,2).

Step-by-step explanation:

Convert to vertex form y = a(x - b)^2 + c where (b, c) is the vertex.

y =x^2 - 4x + 6

y = (x - 2)^2 - 4 +6

y = (x - 2)^2 + 2.

Therefore the vertex is (2, 2).

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