Respuesta :

jacob193

Answer:

Choice A) a² - 9a - 11.

Step-by-step explanation:

Separate the terms by the power of the variable, [tex]a[/tex].

Terms with power 2 on [tex]a[/tex]:

  • First equation: 6a²;
  • Second equation: -5a².

Terms with power 1 on [tex]a[/tex]:

  • First equation: -17a;
  • Second equation: 8a.

Terms with power 0 on [tex]a[/tex], which are also known as constant terms:

  • First equation: [tex]-9[/tex];
  • Second equation: [tex]-2[/tex].

Apply the distributive property of multiplication in reverse. In other words, factor out terms with the same power and add the coefficients.

Terms with power 2 on [tex]a[/tex]:

[tex]6a^{2} + (-5a^{2}) = (6 + (-5))a^{2} = a^{2}[/tex].

Terms with power 1 on [tex]a[/tex]:

[tex]-17 a + 8a = ((-17) + 8)a = -9a[/tex].

Constant terms:

[tex](-9) + (-2) = -11[/tex].

Add the sum of the individual terms to find the sum of the two polynomials:

[tex]a^{2} + (- 9a) +(- 11) = a^{2}-9a -11[/tex].

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