Answer:
The answer is c).
Explanation:
[tex]v_0 = 2 \frac{m}{s} \\ v_1 = 10 \frac{m}{s} \\ t = 10s \\ \\ s = unknown \\ \\ a = \frac{v_1 - v_0}{t} \\ a = \frac{10 \frac{m}{s} - 2 \frac{m}{s} }{10s} = 0.8 \frac{m}{ {s}^{2} } \\ \\ s = v_0t + \frac{a {t}^{2} }{2} \\ s = 2 \frac{m}{s} \times 10s + \frac{0.8 \frac{m}{ {s}^{2} } \times {(10s)}^{2} }{2} = 60m[/tex]
