find the slope intercept form for the equation of a line which passes through the point( 7, 4) and the origin​

Respuesta :

Answer:

y = [tex]\frac{4}{7}[/tex]x

Explanation:

Slope-intercept form is y = mx + b

m is the slope (rise over run)

b is the y-intercept (where the line crosses the y-axis)

To get the slope, use the formula [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1}}[/tex]. It doesn't matter which set of coordinates is which pair.

(x₁,y₁) = (7,4)

(x₂,y₂) = (0,0)  a.k.a "the origin"

[tex]\frac{0-4}{0-7} = \frac{-4}{-7} = \frac{4}{7}[/tex] = your slope (m)

Now, to get to slope-intercept form, you have to plug what you know into point-slope form, y - y₁ = m(x - x₁).

y₁ = a point on the line

m = slope

x₁ = the matching coordinate to y₁

y - 4 = [tex]\frac{4}{7}[/tex] (x - 7)   Distribute

y - 4 = [tex]\frac{4}{7} x - \frac{4*7}{7}[/tex]   Simplify

y - 4 = [tex]\frac{4}{7}x - 4[/tex]   Add 4 to both sides

y = [tex]\frac{4}{7}[/tex]x + 0 or y = [tex]\frac{4}{7}[/tex]x

Check your work by plugging in your given coordinates:

y = [tex]\frac{4}{7}[/tex]x

0 = [tex]\frac{4}{7}[/tex](0)

0 = 0

and

y = [tex]\frac{4}{7}[/tex]x

4 = [tex]\frac{4}{7}[/tex](7)

4 = [tex]\frac{4*7}{7}[/tex]

4 = 4