Answer:
see explanation
Step-by-step explanation:
Given
f(x) = 3x² - 6x + 1
To express in vertex form
f(x) = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Use the method of completing the square
The coefficient of the x² must be 1, so factor out 3
f(x) = 3(x² - 2x) + 1
add/subtract ( half the coefficient of the x- term )² to x² - 2x
f(x) = 3(x² + 2(- 1)x + 1 - 1) + 1
= 3(x - 1)² - 3 + 1
= 3(x - 1)² - 2 ← in vertex form
with vertex = (1, - 2)
To determine if vertex is a max/ min
• If a > 0 then minimum
• If a < 0 then maximum
here a = 3 > 0 ⇒ minimum at (1, - 2)
The minimum value is the y- coordinate of the vertex, that is
minimum value = - 2
