Answer:
[tex]\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}[/tex]
Explanation:
(a) Balanced equation
Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag
(b) Calculation
You want to convert atoms of Cu to atoms of Ag.
The atomic ratio is ratio is 2 atoms Ag:1 atom Cu
[tex]\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}[/tex]
Answer:
[tex]3.966\times 10^{24} [/tex] pure silver atoms are produced.
Explanation:
[tex]1 mol = N_A=6.022\times 10^{23} mol^{-1}[/tex]
Atoms of copper = [tex]19.83\times 10^{23} [/tex]
Moles of copper = [tex]\frac{19.83\times 10^{23} }{N_A}[/tex]
[tex]=\frac{19.83\times 10^{23} }{6.022\times 10^{23} mol^{-1}}=3.293 mol[/tex]
[tex]Cu + 2AgNO_3\rightarrow Cu(NO_3)_2 + 2Ag[/tex]
According to reaction, 1 mol of copper atoms gives 2 moles of silver atoms.
Then 3.293 moles of moles of copper will give:
[tex]\frac{2}{1}\times 3.293 mol=6.586 mol[/tex]
Number of silver atoms in 6.586 moles of silver:
=[tex]6.586 mol\times 6.022\times 10^{23} mol^{-1}=3.966\times 10^{24} atoms [/tex]
