wrekt95
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30p question

Calculate the missing values.

For the six month period given, Fred wants to calculate the monthly deviation from the average.

Month Sales Average Deviation
July $1,250 1,412.50 -162.50
Aug. $1,700 1,412.50 ( )
Sept. $1,125 1,412.50 ( )
Oct. $1,850 1,412.50 ( )
Nov. $1,500 1,412.50 ( )
Dec. $1,050 1,412.50 ( )

Respuesta :

Subtract the average from the sales to get the deviation.

Aug. 1700 - 1412.50 = 287.50

Sept. 1125 - 1412.50 = -287.50

Oct. 1850 - 1412.50 = 437.50

Nov. 1500 - 1412.50 = 87.50

Dec. 1050 - 1412.50 = -362.50

The monthly deviation from the average exists at 287.50, -287.50, 437.50, 87.50, and -362.50.

Monthly deviation from the average

Estimating the mean average enables you to specify the deviation from the mean by computing the difference between the mean and each value.

Subtract the average from the sales to acquire the deviation.

Aug. 1700 - 1412.50 = 287.50

Sept. 1125 - 1412.50 = -287.50

Oct. 1850 - 1412.50 = 437.50

Nov. 1500 - 1412.50 = 87.50

Dec. 1050 - 1412.50 = -362.50

The monthly deviation from the average exists at 287.50, -287.50, 437.50, 87.50, and -362.50.

To learn more about the monthly deviation from the average

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