A soccer player is running at a constant speed of 1.8 m/s when she speeds up in the same direction with an acceleration of 0.50 m/s2. What will be her final speed if she accelerates for a total distance of 10.0 meters?

Respuesta :

Answer:

3.6 m/s

Explanation:

v² = v₀² + 2a(x - x₀)

v² = (1.8 m/s)² + 2 (0.50 m/s²) (10.0 m)

v = 3.6 m/s

Answer:

Final speed, v = 3.63 m/s

Explanation:

It is given that,

Initial speed of the player, u = 1.8 m/s

Acceleration of the player, [tex]a=0.5\ m/s^2[/tex]

Distance, s = 10 m

We need to find the final speed of the player. Let it is given by v. Using third equation of motion as :

[tex]v^2-u^2=2as[/tex]

[tex]v^2=2as+u^2[/tex]

[tex]v^2=2\times 0.5\times 10+(1.8)^2[/tex]

v = 3.63 m/s

So, the final speed of the player is 3.63 m/s. Hence, this is the required solution.