Answer:
The ball to hit the ground in 0.53 s.
Explanation:
Given that,
Height = 1.4 m
Time t = 0.53 s
Initial speed = 35 m/s
We need to calculate the time when the ball to hit the ground
Using equation of motion
[tex]s_{y}=u_{y}t-\dfrac{1}{2}gt^2+h_{0}[/tex]
Where, s= vertical height
u= vertical velocity
t = time
h = height
Put the value in equation
[tex]0=0-\dfrac{1}{2}\times9.8\times t^2+1.4[/tex]
[tex]t^2=\dfrac{1.4}{4.9}[/tex]
[tex]t=\sqrt{\dfrac{1.4}{4.9}}[/tex]
[tex]t=0.53\ s[/tex]
Hence, The ball to hit the ground in 0.53 s.
