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You work as a cashier for a bookstore and earn $6 per hour. You also baby sit and earn $6 per hour. You want to earn at least $60 per week, but would like to work no more than 12 hours per week.

Which system of inequalities, along with y ≥ 0 and x ≥ 0, would you use to solve the real-world problem?

Respuesta :

luisejr77

Answer:

[tex]6x + 6y \geq 60[/tex]

[tex]x +y \leq 12[/tex]

[tex]x\geq 0[/tex]

[tex]y\geq 0[/tex]

Step-by-step explanation:

Call x the number of hours you work in the library

Let's call y the number of hours that you work as babysitter

You need to earn more than $ 60 per week, then:

[tex]6x + 6y \geq 60[/tex]

You want to work no more than 12 hours per week. So:

[tex]x +y \leq 12[/tex]

Finally, the system of inequalities that you will obtain is:

[tex]6x + 6y \geq 60[/tex]

[tex]x +y \leq 12[/tex]

[tex]x\geq 0[/tex]

[tex]y\geq 0[/tex]

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