An us bomber is flying horizontally at 300 mph at an altitude of 610 m. its target is an iraqi oil tanker crusing 25kph in the same direction and same vertical plane. what horizontal distance behind the tanker must the pilot observe before he releases the shell to score a direct hit

Distance is a numerical representation of the distance between two objects or locations. The horizontal distance behind the tanker will be 1419.19 m.

What is the distance?

Distance is a numerical representation of the distance between two objects or locations. The distance can refer to a physical length or an estimate based on other factors in physics or common use.

The given data in the problem is ;

v₁ is the horizontal flying velocity = 300 m/h

H is the altitude = 610 m

v₂ is he cruise velocity= 25km/h

If t is the time taken the shell drops to the tanker from the height h is found by the formula;

[tex]\rm H =\frac{1}{2} gt^2 \\\\ \rm t=\sqrt{\frac{H}{2g} } \\\\ \rm t=\sqrt{2gh} \\\\ \rm t=\sqrt{2\times 610 \times 9.81} \\\\ \rm t=11.16 \sec[/tex]

The velocity of bomber obtained after unit conversion;

[tex]V_{12}=300\times 1.60 = 482.802[/tex]

Relative velocity is defined as the velocity of an object with respect to the other object.

Relative velocity=482.802 kph-25 kph=457.802 kph

In one hour there are 3600 seconds then the conversion is found by;

On changing 11.16 seconds to hours we found;

[tex](\frac{11.16}{3600} )=0.0031 \ hours.[/tex]

The range is the horizontal distance which is given by ;

Range= Initial velocity×time taken to hit the tanker.

[tex]\rm R= v \times t \\\\ \rm R= 457.8\times 0.0031\\\\ \rm R= 1.41918\ Km \\\\ \rm R=1419.19 m[/tex]

Hence the horizontal distance behind the tanker will be 1419.19 m.

To learn more about the distance refer to the link;

https://brainly.com/question/26711747