Answer:
1440 N
Explanation:
The electrostatic force between the two charges is given by:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=9.00 \cdot 10^9 N m^2 C^{-2}[/tex] is the Coulomb's constant
[tex]q_1 = q_2 = -8.00 \cdot 10^{-5} C[/tex] is the value of each charge
r = 20.0 cm = 0.20 m is the separation between the charges
Substituting numbers into the equation, we find
[tex]F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(-8.00 \cdot 10^{-5}C)^2}{(0.20 m)^2}=1440 N[/tex]
