Explanation:
It is given that,
Number of turns in primary coil, [tex]N_p=60[/tex]
Number of turns in secondary coil, [tex]N_s=300[/tex]
Voltage in primary coil, [tex]V_p=120\ V[/tex]
Current in primary coil, [tex]I_p=2\ A[/tex]
We have to find the voltage and current in the secondary coli. Firstly calculating the voltage in secondary coil as :
[tex]\dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}[/tex]
[tex]\dfrac{60}{300}=\dfrac{120}{V_s}[/tex]
[tex]V_s=720\ Volts[/tex]
Now, calculating the current present in the secondary coil as :
[tex]\dfrac{N_p}{N_s}=\dfrac{I_s}{I_p}[/tex]
[tex]\dfrac{60}{300}=\dfrac{I_s}{2\ A}[/tex]
[tex]I_s=0.4\ A[/tex]
Hence, this is the required solution.
