Answer:
0.009 mol.
Explanation:
M = (no. of moles of acetic acid)/(Volume of the solution (L)).
M = 0.9 M, Volume of the solution = 10.0 mL = 0.01 L.
∴ no. of moles of acetic acid = (M)(Volume of the solution (L)) = (0.9 M)(0.01 L) = 0.009 mol.
Answer:
The number of acetic acid moles is 0.0090 in 10 ml of the solution.
Explanation:
[tex]Molarity=\frac{Moles}{Volume (L)}[/tex]
Let the moles acetic acid in vinegar be n.
Molarity of the vinegar solution = 0.90 M
Volume of the vinegar solution = 10 mL = 0.010 L
1 mL = 0.001 L
[tex]0.90M=\frac{n}{0.010 L}[/tex]
[tex]n=0.90 M\times 0.010 L=0.0090 mol[/tex]
The number of acetic acid moles is 0.0090 in 10 ml of the solution.
