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The rectangular backboard of a basketball court needs to be assembled. Its area is given as 18,900 cm2 and the width as 1.8 m.
What is the backboard’s length in metres?
m

The seating space around the basketball court is shown below:

What is the perimeter of the total area?
m
What is the area of the seating space?
m2

Respuesta :

Answer:

length=1.05m

perimeter=2.7m

Step-by-step explanation:

18900 in m^2=1.89 m^2

area=length*width

1.89=length*1.8 m

length=1.89Ă·1.8

length=1.05 m

perimeter=(l+w) 2

perimeter=(1.05+1.8)2

perimeter=2.85Ă—2

perimeter=2.7 m

Lanuel

a. The rectangular backboard’s length in meters is 1.05 meters.

b. The perimeter of the total area in meters is 5.7 meters.

Given the following data:

  • Area of rectangular backboard = 18,900 [tex]cm^{2}[/tex]
  • Width of rectangular backboard = 1.8 meters.

Conversion:

10,000 [tex]cm^{2}[/tex] = 1 [tex]m^2[/tex]

18,900 [tex]cm^{2}[/tex] = X [tex]m^2[/tex]

Cross-multiplying, we have:

[tex]X = \frac{18900}{10000}[/tex]

X = 1.89 [tex]m^2[/tex]

a. To find the backboard’s length in meters:

Mathematically, the area of a rectangle is given by the formula;

[tex]A = LW\\\\1.89 = L(1.8)\\\\L = \frac{1.89}{1.8}[/tex]

Length, L = 1.05 meters.

b. To find the perimeter of the total area in meters:

Mathematically, the perimeter of a rectangle is given by the formula;

[tex]Perimeter = 2(L+W)[/tex]

Substituting the values into the formula, we have;

[tex]Perimeter = 2(1.05+1.8)\\\\Perimeter = 2(2.85)[/tex]

Perimeter = 5.7 meters

Find more information: brainly.com/question/897975

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