Answer:
Net force, F = 44.66 N
Explanation:
It is given by,
Initial velocity of the person, u = 0
Final velocity of the person, v = 0.68 m/s
Distance, s = 0.428 m
Combined mass of the person and the kayak, m = 82.7 kg
We need to find the net force acting on the kayak i.e.
F = ma...........(1)
Firstly, we will calculate the value of "a" from third equation of motion as :
[tex]v^2-u^2=2as[/tex]
[tex]a=\dfrac{v^2-u^2}{2s}[/tex]
[tex]a=\dfrac{(0.68\ m/s)^2-0}{2\times 0.428\ m}[/tex]
[tex]a=0.54\ m/s^2[/tex]
Put the value of a in equation (1) as :
[tex]F=82.7\ kg\times 0.54\ m/s^2[/tex]
F = 44.66 N
So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.
