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|| Suppose a plane accelerates from rest for 30 s, achieving a takeoff speed of 80 m/s after traveling a distance of 1200 m down the runway. A smaller plane with the same acceleration has a takeoff speed of 40 m/s. Starting from rest, after what distance will this smaller plane reach its takeoff speed?

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Blacklash

Answer:

600 m is required for smaller plane to reach its takeoff speed.

Explanation:

We have equation of motion  

          80 = 0 + a x 30

          a = 2.67 m/s²

Now finding distance traveled by second flight

       v² = u²+2as

      40² = 0²+2 x 2.67 x s

       s = 300 m

So 300 m is required for smaller plane to reach its takeoff speed.

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