Answer:
(a) 0.139 N/m
(b) 2.83 Hz
Explanation:
(a) m = 0.22 g = 0.22 x 10^-3 kg
f = 4 Hz
The formula for the frequency of spring is given by
f = [tex]f = \frac{1}{2\pi }\times \sqrt{\frac{k}{m}}[/tex]
Where, k be the spring constant
[tex]4 = \frac{1}{2\times 3.14 }\times \sqrt{\frac{k}{0.22\times 10^{-3}}}[/tex]
k = 0.139 N/m
(b)
m = 0.44 g = 0.44 x 10^-3 kg,
k = 0.139 N/m
Let the frequency be f.
f = [tex]f = \frac{1}{2\pi }\times \sqrt{\frac{k}{m}}[/tex]
[tex]f = \frac{1}{2\times 3.14 }\times \sqrt{\frac{0.139}{0.44\times 10^{-3}}}[/tex]
f = 2.83 Hz
