bearing in mind that the rate of change will just be the slope or namely the derivative of the expression.
[tex]\bf f(x)=3+e^x(x-5)^3\implies \cfrac{df}{dx}=0+\stackrel{\textit{product rule}}{e^x(x-5)^3+\stackrel{\textit{chain rule}}{e^x\cdot 3(x-5)^2\cdot 1}} \\\\\\ \cfrac{df}{dx}=e^x(x-5)^3+3e^x(x-5)^2\implies \cfrac{df}{dx}=\stackrel{\textit{common factor}}{e^x(x-5)^2[(x-5)+3]} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \cfrac{df}{dx}=e^x(x-5)^2(x-2)~\hfill[/tex]
