Answer:
105 frames
Step-by-step explanation:
Given that 25 frames are played per second
25 frames= 1 sec
The video already played 3 and 2/5 seconds before the player started to count 0
Write 3 and 2/5 seconds as an improper fraction
=(5*3)+2 / 5 = 17/5 seconds
Multiply by 25 frames
17/5 *25 =85 frames
So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.
190-85=105 frames.
Answer:
The number of frames when the time was equal to [tex]-3\frac{2}{5}[/tex] seconds is 125.
Step-by-step explanation:
It is given that the player began counting at 0 seconds, even though the video had already played 190 frames. The video plays 25 frames per second.
The slope intercept form of linear function is
[tex]y=mx+b[/tex]
where, m is rate of change and b is initial value.
It means the initial number of frames = 190
Change in frames per second = 25
The equation that represents the number of frames after x seconds is
[tex]y=25x+190[/tex] .... (1)
We need to find the number of frames when the time was equal to [tex]-3\frac{2}{5}[/tex] seconds.
[tex]x=-3\frac{2}{5}=-\frac{13}{5}[/tex]
Substitute [tex]x=-\frac{13}{5}[/tex] in equation (1),
[tex]y=25(-\frac{13}{5})+190[/tex]
[tex]y=-65+190[/tex]
[tex]y=125[/tex]
Therefore the number of frames when the time was equal to [tex]-3\frac{2}{5}[/tex] seconds is 125.
