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How many electrons does a single oxygen gain or lose in the following reaction?
H 2 + O 2 → H 2 O

Respuesta :

Answer:

it gains 2 electrons

Explanation:

atoms want to be more stable, for oxygen it's number is 8, 2 less than the stable ring of 10. and hydrogen has a single electron, 1 less than the stable ring of 2. so oxygen takes 2 electrons 2 make it stable and hydrogen becomes attatched to the oxygen atom to form a covalent bond

Answer: A single oxygen atom is gaining 2 electrons in the given reaction.

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

[tex]X\rightarrow X^{n+}+ne^-[/tex]

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

[tex]X^{n+}+ne^-\rightarrow X[/tex]

For the given chemical reaction:

[tex]H_2+\frac{1}{2}O_2\rightarrow H_2O[/tex]

The half cell reactions for the above reaction follows:

Oxidation half reaction:  [tex]H_2\rightarrow 2H^{+}+2e^-[/tex]

Reduction half reaction:  [tex]\frac{1}{2}O_2+2e^-\rightarrow O^{2-}[/tex]

As, hydrogen is loosing 2 electrons to form hydrogen cation. Thus, it is getting oxidized. Oxygen is gaining 2 electrons to form oxygen anion. Thus, it is getting reduced.

Hence, a single oxygen atom is gaining 2 electrons in the given reaction.