Answer:
-28
Step-by-step explanation:
[tex]-(2-2^3)^2-4 \cdot (-2)[/tex]
We going to use PE(MD)(AS).
So P means ( ).
We do have operations to perform in the ( ).
We have [tex]2-2^3[/tex] in the first set of ( ) and (-2) in the second set of ( ).
There are no operations in the second set containing -2.
So we are just focusing on the [tex]2-2^3[/tex] right now.
You have subtract and exponent here.
Exponents come first in PE(MD)(AS) so we will perform that first.
[tex]2-2^3=2-8=-6[/tex]
Let's go back to the original problem now.
[tex]-(2-2^3)^2-4 \cdot (-2)[/tex]
[tex]-(-6)^2-4 \cdot(-2)[/tex]
Now there are no longer any operations grouped together by use of ( ).
It on to the rest of PE(MD)(AS).
So now we are doing the E part, the exponents.
[tex]-(36)-4 \cdot(-2)[/tex]
Now there is multiplication and subtraction left.
(MD) comes before (AS) so we do the multiplication and then the subtraction. So I'm going to do 4(-2) now:
[tex]-(36)-(-8)[/tex]
Subtraction is addition of the opposite so you could write:
[tex]-(36)+8[/tex]
We don't really need ( ) around the first number:
[tex]-36+8[/tex]
36-8 is 28 but since 36>8 and 36 has a negative sign on it, the answer is -28.
