Answer:
0.647 nC
Explanation:
The force experienced by a charge due to the presence of an electric field is given by
[tex]F=qE[/tex]
where
q is the charge
E is the magnitude of the electric field
In this problem, each antenna is modelled as it was a single point charge, experiencing a force of
[tex]F=5.50\mu N = 5.50\cdot 10^{-6} N[/tex]
Therefore, if the electric field magnitude is
[tex]E=8.50 kN/C = 8500 N/C[/tex]
Then the charge on each antenna would be
[tex]q=\frac{F}{E}=\frac{5.50\cdot 10^{-6} N}{8500 N/C}=6.47\cdot 10^{-10} C = 0.647 nC[/tex]
