Respuesta :

Edufirst

Answer:

  • 1,310 lb

Explanation:

1) Calculate the volume of the water in the tank.

  • Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
  • Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
  • Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.

2) Calculate the weight of 21 ft³ of water.

Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:

  • 62.4 lb / 1 ft³ = x / 21 ft³

Solve for x:

  • x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.

So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.

Evadin2019

The water in the tank's weigh is 1310.4 pounds/feet³

Further Explanation

From the problem above we know that:

The water's weighs = 62.4 pounds/foot³

The tank measurement = 7 ft x 4 ft x 9 inch

First step

We are going to convert the tank's measurement into foot

1 inch = 0.083 foot, so 9 inches would be

[tex]9 x 0.083 ft = 0.75 ft[/tex]

Second step

We are going to find the tank's volume

[tex] 7 ft x 4 ft x 0.75 ft = 21 [/tex] feet³

with the proportional calculation we going to find the tank's water weigh when it is full. The tank's water weigh would be in x variable

[tex]\frac{water weigh}{volume}  =\frac{62.4 pounds}{1 ft} = \frac{x}{21}[/tex]

[tex]x = 62.4 pounds x 21 feet³ = 1310. 4 pounds[/tex]

So, the weigh of the water in tank is 1310.4 pounds/feet³

Learn more

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Keywords: weigh, tank's volume, calculate volume

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