contestada

The acceleration of a baseball pitcher's hand as he delivers a pitch is extreme. For a professional player, this acceleration phase lasts only 50 ms, during which the ball's speed increases from 0 to about 90 mph, or 40 m/s.

What is the force of the pitcher's hand on the 0.145 kg ball during this acceleration phase?

Respuesta :

Answer:

force = 116N

Explanation:

given,

mass of ball  = 0.145 kg

final velocity (v) = 40 m/s

initial velocity (u) = 0

time (t) =  50 ms

[tex]force = \dfrac{change\ in\ momentum}{time} \\force = \dfrac{m\times \Delta v}{t}\\force = \dfrac{0.145\times(40-0)}{50 \times 10^{-3}}[/tex]

force= 116 N

hence, force exerted by the pitcher on the ball will be equal to 116N

Otras preguntas