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An ideal gas in a sealed container has an initial volume of 2.70 L. At constant pressure, it is cooled to 17.00 ∘C, where its final volume is 1.75 L. What was the initial temperature?

Respuesta :

Answer:

Initial temperature of the ideal gas is 447.4 K.

Explanation:

It is given that,

Initial volume, V₁ = 2.7 L

Final volume, V₂ = 1.75 L

Final temperature, T₂ = 17 °C = 290 K

We need to find the initial temperature of the gas. It can be calculated using Charles' law as :

[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]

[tex]T_1=\dfrac{V_1T_2}{V_2}[/tex]

[tex]T_1=\dfrac{2.7\ L\times 290\ K}{1.75\ L}[/tex]

[tex]T_1=447.4\ K[/tex]

So, the initial temperature of the ideal gas in a sealed container is 447.4 K. Hence, this is the required solution.

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