Answer:
c. x = 6 only
Step-by-step explanation:
In order to calculate the zeros of f(x), we need to set it equal to zero and find the corresponding values of x.
[tex]x^{2}-12x+36=0[/tex]
Using the midterm breaking, we can split -12x into two such terms whose sum will be -12x and product will be 36x². These two terms are -6x and -6x
So, the above expression can be written as:
[tex]x^2-6x-6x+36=0\\\\ x(x-6)-6(x-6)=0\\\\ (x-6)(x-6)=0\\\\ (x-6)^{2}=0\\\\ x-6=0\\\\ x=6[/tex]
This means, the zero of f(x) occurs at x = 6 only.
