Answer:
The length of rectangle is 6 units and the width is 1.5 units
Step-by-step explanation:
Let
L -----> the length of rectangle
W ----> the width of rectangle
we know that
The area of rectangle is equal to
[tex]A=LW[/tex]
we have
[tex]A=9\ units^{2}[/tex]
so
[tex]9=LW[/tex] -----> equation A
A rectangle width is one fourth it’s length
so
[tex]W=\frac{1}{4}L[/tex] ----> equation B
substitute equation B in equation A and solve for L
[tex]9=L(\frac{1}{4}L)[/tex]
[tex]L^{2}=9*4[/tex]
[tex]L^{2}=36[/tex]
take square root both sides
[tex]L=6\ units[/tex]
Find the value of W
[tex]W=\frac{1}{4}(6)[/tex]
[tex]W=1.5\ units[/tex]
