[tex]\huge{\boxed{y+5=2(x-4)}}[/tex]
Point-slope form is [tex]y-y_1=m(x-x_1)[/tex], where [tex]m[/tex] is the slope of the line and [tex](x_1, y_1)[/tex] is a known point on the line.
Substitute the values. [tex]y-(-5)=2(x-4)[/tex]
Simplify the negative subtraction. [tex]\boxed{y+5=2(x-4)}[/tex]
Note: This equation is in point-slope form. If you require or prefer another form, please let me know in a comment below.
Answer:
y = 2x - 13
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 2, hence
y = 2x + c ← is the partial equation
To find c substitute (4, - 5) into the partial equation
- 5 = 8 + c ⇒ c = - 5 - 8 = - 13
y = 2x - 13 ← equation of line
