Answer:
313.6 m downward
Explanation:
The distance covered by the bullet along the vertical direction can be calculated by using the equation of motion of a projectile along the y-axis.
In fact, we have:
[tex]y(t) = h +u_y t + \frac{1}{2}at^2[/tex]
where
y(t) is the vertical position of the projectile at time t
h is the initial height of the projectile
[tex]u_y = 0[/tex] is the initial vertical velocity of the projectile, which is zero since the bullet is fired horizontally
t is the time
a = g = -9.8 m/s^2 is the acceleration due to gravity
We can rewrite the equation as
[tex]y(t)-h = \frac{1}{2}gt^2[/tex]
where the term on the left, [tex]y(t)-h[/tex], represents the vertical displacement of the bullet. Substituting numbers and t = 8 s, we find
[tex]y(t)-h= \frac{1}{2}(-9.8)(8)^2 = -313.6 m[/tex]
So the bullet has travelled 313.6 m downward.
