Answer: The most likely identity of the substance is iron.
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.
[tex]Q=m\times c\times \Delta T[/tex]
Q = Heat absorbed=[tex]1.071\times 10^2[/tex] Joules
m= mass of substance = 11.9 g
c = specific heat capacity = ?
Initial temperature of the water = [tex]T_i[/tex] = 25.0°C
Final temperature of the water = [tex]T_f[/tex] = 45.0°CChange in temperature ,[tex]\Delta T=T_f-T_i=(45-25)^0C=20^0C[/tex]
Putting in the values, we get:
[tex]1.071\times 10^2=11.9\times c\times 20^0C[/tex]
[tex]c=0.45J/g^0C[/tex]
The specific heat of 0.45 is for iron and thus the substance is iron.
