A police officer is chasing a purse-snatcher down a street. The thief
starts 9 meters ahead of the officer and can run 20 meters in 4 second
(5 m/s). The police officer can run 32 meters in 4 seconds (8 m/s). How long will it take the officer to catch the thief?

Respuesta :

Answer:

3 seconds

Explanation:

We can give an expression for the position of both the thief and of the police officer at time t.

The position of the thief at time t is given by

[tex]x_t = 9 + 5t[/tex]

where 9 is its initial position in m and 5 is its speed in m/s.

Instead, the position of the police officer at time t is given by

[tex]x_o = 0+8t[/tex]

where 0 is its initial position in m and 8 is its speed in m/s.

The police officer will catch the thief when their position will be equal, so

[tex]x_t = x_o[/tex]

By solving,

[tex]9+5t=8t\\3t=9\\t=3 s[/tex]

Answer:

It would take the police officer about 3 seconds to catch the purse-snatcher.